2x^2-41x+132=0

Solution for 2x^2-41x+132=0 equation:

Simplifying
2x2 + -41x + 132 = 0

Reorder the terms:
132 + -41x + 2x2 = 0

Solving
132 + -41x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -1x)(33 + -2x) = 0

Subproblem 1
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Subproblem 2
Set the factor '(33 + -2x)' equal to zero and attempt to solve:

Simplifying
33 + -2x = 0

Solving
33 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-33' to each side of the equation.
33 + -33 + -2x = 0 + -33

Combine like terms: 33 + -33 = 0
0 + -2x = 0 + -33
-2x = 0 + -33

Combine like terms: 0 + -33 = -33
-2x = -33

Divide each side by '-2'.
x = 16.5

Simplifying
x = 16.5
Solution
x = {4, 16.5}